[Solved] invalid conversion from 'char' to 'char*'

Yash

@char *argv[30];
QStringList m; m <<"dd" <<"ss";

for (int i = 0; i < m.count (); i++)
argv[i] = (m.at (i).data ())->toLatin1 ();@

error: invalid conversion from 'char' to 'char*'

Where should I put & ?

t3chNo

@(m.at (i).data ())@ returns QChar*

@->toLatin1 ()@ returns char. argv[i] is char*.

i think you want sth like this:
@argv[i] = m.at(i).toLocal8Bit().data()@

dangelog

[quote author="t3chNo" date="1293294118"]@(m.at (i).data ())@ returns QChar*

@->toLatin1 ()@ returns char. argv[i] is char*.

i think you want sth like this:
@argv[i] = m.at(i).toLocal8Bit().data()@[/quote]

... which is completely invalid, you can't store what data() returns!

Immii

There is one FAQ about the conversion of" QString to char":http://developer.qt.nokia.com/faq/answer/how_can_i_convert_a_qstring_to_char_and_vice_versa see if this is of any help to you.

t3chNo

yes, sorry. proper way is:
@argv[i] = new char[32];
strncpy(argv[i], m.at(i).toLocal8Bit().data(), 32);@
[quote author="peppe" date="1293299729"]
[quote author="t3chNo" date="1293294118"]@(m.at (i).data ())@ returns QChar*

@->toLatin1 ()@ returns char. argv[i] is char*.

i think you want sth like this:
@argv[i] = m.at(i).toLocal8Bit().data()@[/quote]

... which is completely invalid, you can't store what data() returns!
[/quote]

Yash

It's working :) Thanks
[quote author="t3chNo" date="1293305300"]yes, sorry. proper way is:
@argv[i] = new char[32];
strncpy(argv[i], m.at(i).toLocal8Bit().data(), 32);@
[quote author="peppe" date="1293299729"]
[quote author="t3chNo" date="1293294118"]@(m.at (i).data ())@ returns QChar*

@->toLatin1 ()@ returns char. argv[i] is char*.

i think you want sth like this:
@argv[i] = m.at(i).toLocal8Bit().data()@[/quote]

... which is completely invalid, you can't store what data() returns!
[/quote]

[/quote]