QRect constructor

[Kolyunya]

I don't really know, where to post this, sorry.

I just want to share some thoughts and to know your opinion. While working with Qt I've needed many times to construct a QRect from two random points. This means, I do not know what are they: topLeft or topRight or bottomLeft or bottomRight.

So I think the QRect needs a constructor from two random points. What do you think?

Example: user selects some area on a "desktop", we get two points: where he presses mouse and where he releases it. He can make a selection in any direction.

I do know how to solve this. I'm talking about adding this feature to some or the next releases of Qt. I think it would be useful.

[messi]

Hi Kolyunya

What you would need is a function which checks from where to where the user selected the area on the desktop. There are four possibilities for a rect. So I don't think that a new constructor in QRect is really necessary but thats only my opinion.

Cheers J

[Jeroentjehome]

Hmm, just catch the mouse event and the "start" position and "stop" position would give a positive of negative value. Put those three (2 points and the direction) in a signal and the QRect will be able to be made with the given constructors. The QRect shouldn't have any idea why/how or who did create the rectangle IYAM, but your application might require it anyway.
Happy coding!

[andre]

So, why don't you do this then?
@
QRect myRect = QRect(point1, point2).normalized();
@

I don't think a special constructor is needed for this.

[vittalonline]

Andre You are a great Qt Specialist...