<![CDATA[Q_ARG return type in Qt 6.5]]>According to the documentation here, Q_ARG should return a QGenericArgument; however, in my testing it is returning a QMetaMethodArgument.

The following simple line which worked in Qt 5.15:

QGenericArgument arg = Q_ARG(int,1);

has an error in Qt 6.5, "No viable conversion from 'QMetaMethodArgument' to 'QGenericArgument'. What am I doing wrong, or is this a mistake in the docs?

]]>https://forum.qt.io/topic/144875/q_arg-return-type-in-qt-6-5RSS for NodeWed, 08 Apr 2026 13:46:33 GMTThu, 04 May 2023 13:44:18 GMT60<![CDATA[Reply to Q_ARG return type in Qt 6.5 on Mon, 18 Sep 2023 06:25:04 GMT]]>I reviewed the old code and added the following definition:

#define Q_ARG_OLD(type, data) QArgument<type >(#type, data)
]]>https://forum.qt.io/post/773024https://forum.qt.io/post/773024Mon, 18 Sep 2023 06:25:04 GMT<![CDATA[Reply to Q_ARG return type in Qt 6.5 on Fri, 05 May 2023 07:57:54 GMT]]>@flatland3r
In any case, since the returned class is part of private API and not supposed to be used directly, I would suggest

auto arg = Q_ARG(int,1);
]]>https://forum.qt.io/post/757154https://forum.qt.io/post/757154Fri, 05 May 2023 07:57:54 GMT<![CDATA[Reply to Q_ARG return type in Qt 6.5 on Thu, 04 May 2023 15:42:01 GMT]]>This seems to be an oversight in the documentation - I would suggess creating a bug report so the documentation gets fixed.

]]>https://forum.qt.io/post/757065https://forum.qt.io/post/757065Thu, 04 May 2023 15:42:01 GMT