<![CDATA[Problem with QSqlField.type() (when used with QSqlTableModel)]]>I'm trying to determine the datatype of the columns (fields) of a PostgreSQL database table as rendered by QSqlTableModel. I'm using QSqlField.type() for this:

("model" is a QSqlTableModel)
@
QSqlRecord rec = model->record(1);
QSqlField f = rec.field("name");
QVariant v = f.value();
qDebug() << "Field Value for row 0 and column 1/name (should be Alex)" << v.toString();
QSqlField f2 = rec.field("name");
QVariant t = f2.type();
qDebug() << "Field Type for column 1/name (should be char)" << t.toString();
QSqlField f3 = rec.field("id");
t = f3.type();
qDebug() << "Field Type for column 0/id (should be int)" << t.toString();
@

Unfortunately, this is what I get from the code above:

@
Field Value for row 0 and column 1/name (should be Alex) "Alex"
Field Type for column 1/name (should be char) ""
Field Type for column 0/id (should be int) "0"
@

Does anybody know what is going wrong here?

Thanks

]]>https://forum.qt.io/topic/14062/problem-with-qsqlfield-type-when-used-with-qsqltablemodelRSS for NodeMon, 10 Aug 2026 23:34:30 GMTTue, 14 Feb 2012 20:38:52 GMT60<![CDATA[Reply to Problem with QSqlField.type() (when used with QSqlTableModel) on Wed, 15 Feb 2012 09:13:53 GMT]]>QVariant::Type is an enum (int) type

]]>https://forum.qt.io/post/129095https://forum.qt.io/post/129095Wed, 15 Feb 2012 09:13:53 GMT<![CDATA[Reply to Problem with QSqlField.type() (when used with QSqlTableModel) on Wed, 15 Feb 2012 07:29:51 GMT]]>Thanks! Now it works as expected:

@
Field Value for row 1 and column 1 (should be Alex) "Alex"
Field Type for column 1/name (should be char) QVariant::QString
Field Type for column 0/id (should be int) QVariant::int
@

BTW, the qDebug line should be like this:

@
qDebug() << "Field Type for column 1/name (should be char)" << t;
@

(No .toString() casting)

]]>https://forum.qt.io/post/129072https://forum.qt.io/post/129072Wed, 15 Feb 2012 07:29:51 GMT<![CDATA[Reply to Problem with QSqlField.type() (when used with QSqlTableModel) on Tue, 14 Feb 2012 20:55:56 GMT]]>This is wrong:

@
QVariant t = f2.type();
@

"QSqlField::type() ":/doc/qt-4.8/qsqlfield.html#type returns a QVariant::Type, not a QVariant!

Change your code to this:

@
QVariant::Type t = f2.type();
@

The qDebug() output should print 10, which is QVariant::String.

]]>https://forum.qt.io/post/129031https://forum.qt.io/post/129031Tue, 14 Feb 2012 20:55:56 GMT