How to pass reguaklr expression - from string list ?

Anonymous_Banned275

Another C++ code under construction and I need advise.

cursor = document->find(str);  will accept regular expression , but I am passing plain QString. That is no go.

I like to keep that QString in QStringList , but I do not know how and where to build regular expression - in foreach loop. .

I did try - replacing the QString , but that is wrong - it breaks the QStringList .

QRegularExpression re( [0-F]{2}[:]){5}[0-F]{2}", "([0-F]{2}[:] ) ;

    QStringList BT_Setup[16] = {{  "controller","Powered: yes","Discoverable: no","Pairable: no","Discovering: no",
                                 "([0-F]{2}[:]){5}[0-F]{2}", "([0-F]{2}[:])"  },
                                 {  "contoller", "Remote", "Control"},
                                 {  "contoller", "Remote", "Control"}
    };
    QTextDocument * document = ui->textEdit_35->document();
    QTextCursor cursor = ui->textEdit_35->textCursor();
    QTextCharFormat fmt = cursor.charFormat();
    fmt.setBackground(Qt::green);

    foreach(str, BT_Setup[0])
    { // foreach block
        qDebug() << "DEBUG POINT "  << QString::number(__LINE__);
        qDebug() << "DEBUG POINT "  << str;

      convert str  to regular expression here ?? 

        cursor = document->find(str);
        if(cursor.isNull())
        {
         qDebug() << "FAILED DEBUG POINT "  << QString::number(__LINE__);
        qDebug() << "DEBUG POINT "  << str;
        }
       cursor.setCharFormat(fmt);
    }// foreach block

mrjj

Hi
Since QRegularExpression has a constructor that takes a QString ,
cant you just say

QRegularExpression exp(str);
cursor = document->find( exp);

Anonymous_Banned275

@mrjj Perfect - I just cannot think as a compiler - plain string as regular expression....
SOLVED