One more time Debug operator<<

ofmrew

I have placed```
};
QDebug operator<<(QDebug debug, const Matrix4x4 &m);
#endif // MATRIX4X4_H

outside of the function declaration and  have the implementation:

QDebug operator<<(QDebug debug, const Matrix4x4 &m){
QDebugStateSaver saver(debug);
debug.nospace() << "Row 1" << m.m11 << m.m12 << m.m13 << m.m14<<"\n"
<< "Row 2" << m.m21 << m.m22 << m.m23 << m.m24<<"\n"
<< "Row 3" << m.m31 << m.m32 << m.m33 << m.m34<<"\n"
<< "Row 4" << m.m41 << m.m42 << m.m43 << m.m44;
return debug;
}

The Matrix4x4 I am trying to show is:
"T1"
1 0 0 50
0 1 0 50
0 0 1 100
0 0 0 1
which is defined as  
Matrix4x4  * T1 = Matrix4x4().translate(50.0,50.0,100.0);
and the debug attempt  is 
            qDebug() << T1;
and the output is 
0x20ea2bdcea0
I believe that I am following the Qt code shown in the woboq source code for QTransform. What is wrong?

Christian Ehrlicher

@ofmrew said in One more time Debug operator<<:

Matrix4x4 * T1
qDebug() << T1;

Because T1 is a pointer, you wrote an operator for an object. Pass an object to operator <<

Apart from this I would see a need that a simply Matrix class is used via a pointer, esp. a translate() function should not return a pointer where you can forgot the delete it.

ofmrew

Thanks, qDebug() << *T1; solved the problem, but honestly I believe that I tried that before--must of violated the cardinal rule of debugging: never make more than one change at a time. Again thanks.