How to delete a widget at once in a QLayout?

feiyuhuahuo

I tried this way:

        print(self.main_ui.findChildren(QLabel))
        print(self.main_ui.verticalLayout_6.count())
        item = self.main_ui.verticalLayout_6.takeAt(0)
        item.widget().close()
        self.main_ui.verticalLayout_6.removeWidget(item.widget())
        print(self.main_ui.verticalLayout_6.count())
        print(self.main_ui.findChildren(QLabel))

Though it is deleted from the Layout, it still can be found in self.main_ui. I also tried widget.deleteLater() function, it can delete successfully in self.main_ui, but it can not delete at once.

SGaist

Hi,

What do you mean by "it cannot delete at once" ?

deleteLater will trigger the deletion as soon as possible which is usually enough.

What is your current issue ?
What is your goal ?

feiyuhuahuo

Hi， @SGaist

My initial UI has a QGroupBox names group_box_ok, and you can see from line 739~740 that I want to delete it first. Then I want to add other QGroupBoxes according to class_names. For example, class_names is ('ok', 'dog', 'cat'), then I hope there's only group_box_ok, group_box_dog and group_box_cat in cls_aug_ui. But the result is:

So the old group_box_ok was not deleted at once. The following code raises bugs because there's a duplicated group_box_ok. And I must doing these things in the same function (slot). I want that cls_aug_ui.findChildren(QGroupBox) can not find the old group_box_ok .

SGaist

You can remove the parent of the widget you took out of the layout.

feiyuhuahuo

I found the parent of the widget need to be set as None before removing the widget.
We can remove the widget by this way:

        widget = self.main_ui.verticalLayout_6.takeAt(0).widget()
        widget.setParent(None)
        widget.close()
        self.main_ui.verticalLayout_6.removeWidget(widget)