Solved algorithm fun

Hi all 
Imagine an array of n items. Given an index v, your task is to "normalize" v so that 0 <= v < n. Two catches:
 When the indices extend beyond 09, they don't merely repeat; they "mirror." So, if n = 3,
v v' 0 0 1 1 2 2 3 2 4 1 5 0
 must work for negative values of v.
This didn't seem that complicated at first glance, but I had a heck of a time with it. My solution works, but I'm wondering whether any of you math wizards can simplify it. Here's my solution:
int getReal(int v, int n) { int x; int y; int z; x = abs(v); y = x % (2*n); if (y >= n) { z = n  (x % n)  1; } else { z = x % n; } printf("%3d %3d\n", v, z); return z; }
Thanks...
