Why would anyone write int(qRound(x)) ?

[Bart_Vandewoestyne]

In the legacy codebase I'm working on (dating from Qt 4.8.7 or earlier) I often encounter statements similar to the following:

int y = int(qRound(x));

Looking at the Qt 5 documentation for qRound at https://doc.qt.io/qt-5/qtglobal.html I see that qRound's return type is int. So why on earth would anyone use int(qRound(x)) instead of just qRound(x)? Would there be a good reason for this? Maybe historically? Has qRound always had a return type of int? I'm planning to refactor this and remove the int(.), but first would like to get a second opinion on whether there are pitfalls that I'm not thinking of...

[VRonin]

it has always been an int since before the release of Qt 4.8.7
I think that cast is there as a refuse from the STL (std::round(double) returns a double) and your compiler optimises it away in any case

[Bart_Vandewoestyne]

Thanks for confirming. I'll remove the int(.) and go on with my life ;-)