<![CDATA[Why would anyone write int(qRound(x)) ?]]>In the legacy codebase I'm working on (dating from Qt 4.8.7 or earlier) I often encounter statements similar to the following:

int y = int(qRound(x));

Looking at the Qt 5 documentation for qRound at https://doc.qt.io/qt-5/qtglobal.html I see that qRound's return type is int. So why on earth would anyone use int(qRound(x)) instead of just qRound(x)? Would there be a good reason for this? Maybe historically? Has qRound always had a return type of int? I'm planning to refactor this and remove the int(.), but first would like to get a second opinion on whether there are pitfalls that I'm not thinking of...

]]>https://forum.qt.io/topic/128071/why-would-anyone-write-int-qround-xRSS for NodeTue, 04 Aug 2026 18:27:17 GMTWed, 30 Jun 2021 18:32:24 GMT60<![CDATA[Reply to Why would anyone write int(qRound(x)) ? on Thu, 01 Jul 2021 07:37:04 GMT]]>Thanks for confirming. I'll remove the int(.) and go on with my life ;-)

]]>https://forum.qt.io/post/668229https://forum.qt.io/post/668229Thu, 01 Jul 2021 07:37:04 GMT<![CDATA[Reply to Why would anyone write int(qRound(x)) ? on Wed, 30 Jun 2021 18:47:45 GMT]]>it has always been an int since before the release of Qt 4.8.7
I think that cast is there as a refuse from the STL (std::round(double) returns a double) and your compiler optimises it away in any case

]]>https://forum.qt.io/post/668146https://forum.qt.io/post/668146Wed, 30 Jun 2021 18:47:45 GMT