[MacOs] cocoa = fontengine = freetype doesn't work

SeeLook

Hi.
I have following content of qt.conf in Resources of an app bundle:

[Platforms]
cocoa = fontengine=freetype

[Paths]
Plugins = PlugIns
Imports = Resources/qml
Qml2Imports = Resources/qml

and file is loaded during app launch - when removed, app doesn't run.

Unfortunately freetype is not used that way and app strongly depends on it.

Surprisingly, when app is launched with -platform param:

$myapp -platform cocoa:fontengine=freetype

Freetype is used then.

Although, I found dirty solution, by hardcoding that parameter (in main.cpp):

#if defined (Q_OS_MAC)
    int new_argc = argc + 2;
    std::vector<std::unique_ptr<char>> new_argv_aux(new_argc);
    for (int ii = 0; ii < argc; ++ii) {
      new_argv_aux[ii].reset(new char[strlen(argv[ii]) + 1]);
      strcpy(new_argv_aux[ii].get(), argv[ii]);
    }
    new_argv_aux[argc].reset(new char[strlen("-platform") + 1]);
    strcpy(new_argv_aux[argc].get(), "-platform");
    new_argv_aux[argc + 1].reset(new char[strlen("cocoa:fontengine=freetype") + 1]);
    strcpy(new_argv_aux[argc + 1].get(), "cocoa:fontengine=freetype");

    std::vector<char*> new_argv(new_argv_aux.size());
    for (size_t ii = 0; ii < new_argv_aux.size(); ++ii)
      new_argv[ii] = new_argv_aux[ii].get();

    a = new QApplication(new_argc, new_argv.data());
#else
    a = new QApplication(argc, argv);
#endif

which works, but maybe there is something easier and cleaner.
Have you heard about better solution?

SGaist

Hi,

I haven't tested it but based on the documentation, I think it should be something like:

[Platform]
CocoaArguments = fontengine=freetype

If not Cocoa, maybe macOS.

SeeLook

@SGaist Thank You a milion.

[Platform]
CocoaArguments = fontengine=freetype

is the correct incantation