How to get the selection model from QSqlTableModel

[Infinity]

Does the QSqlTableModel know which row is selected by a QTableView. I have something like this:

QSqlTableModel *m_accountModel = new QSqlTableModel(this);
model.setTable("account");
model.select();
...
m_ui->tableViewAccount->setModel(m_accountModel);
m_ui->tableViewAccount->resizeColumnsToContents();
m_ui->tableViewAccount->horizontalHeader()->setStretchLastSection(true);
m_ui->tableViewAccount->setSelectionBehavior(QAbstractItemView::SelectRows);
m_ui->tableViewAccount->setSelectionMode(QAbstractItemView::SingleSelection);
m_ui->tableViewAccount->setEditTriggers(QAbstractItemView::NoEditTriggers)

Now I would like to get the selection of m_ui->tableViewAccount out of the m_accountModel. At the moment I'm doing it like this:

void FormAccount::on_selectionChanged(const QItemSelection &selected, const QItemSelection &deselected)
{
    Q_UNUSED(deselected)

    if (m_ui->tableViewAccount->selectionModel()->hasSelection()) {
        qDebug() << "selection:" << selected;
    }

Is it possible to get the selection directly from the model without using FormAccount::on_selectionChanged()? Or is there an easier and cleaner way to achive this.

[VRonin]

The model doesn't know the selection (it's always useful to remember that 1 model can be attached to multiple views and they can have different selections so it can't be a property of the model).
You can get it from the view using m_ui->tableViewAccount->selectionModel()->selectedIndexes() without using the signal however if that's what you want

[Infinity]

@VRonin That makes perfect sense. :-) Thank you very much.