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    Call for Presentations - Qt World Summit

    Solved Connecting to statusBar()->showMessage gives compile time error in new syntax

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    • O
      ofmrew @JonB last edited by

      @jonb

      Here is a lambda I use to create a QString for statusBar:

          connect(ui->unitVector, &QPushButton::clicked, [=](){
                                                      ui->canvas->go.setFlagAndResetAngle(4);
                                                      QString s;
                                                      s.append("Rotation about Unit Vector ");
                                                      s.append(ui->canvas->go.uv.toString());
                                                      ui->statusBar->showMessage(s, 0);});
      
      JonB 1 Reply Last reply Reply Quote 0
      • JonB
        JonB @ofmrew last edited by

        @ofmrew
        But @sandro4912 is asking

        how to pass the string send from transactionStarted to statusBar()->showMessage()

        hence my suggestion; how is yours to do with passing a parameter on to the lambda??

        1 Reply Last reply Reply Quote 0
        • J.Hilk
          J.Hilk Moderators @JonB last edited by

          @jonb said in Connecting to statusBar()->showMessage gives compile time error in new syntax:

          @sandro4912
          I'm throwing my hat in because I'm not C++, but don't you do that by specifying the lambda as:

          connect(&thread, &TransactionThread::transactionStarted, [=](const QString &text)
              {
                  statusBar()->showMessage(text);  // how to enter the text send with transactionStarted?
              });
          
          

          absolutely correct!👍
          just one caveat, you can, but you shall not omit the return type

          connect(&thread, &TransactionThread::transactionStarted, [=](const QString &text)->void{});
          

          Be aware of the Qt Code of Conduct, when posting : https://forum.qt.io/topic/113070/qt-code-of-conduct

          Qt Needs YOUR vote: https://bugreports.qt.io/browse/QTQAINFRA-4121


          Q: What's that?
          A: It's blue light.
          Q: What does it do?
          A: It turns blue.

          JonB 1 Reply Last reply Reply Quote 3
          • JonB
            JonB @J.Hilk last edited by JonB

            @j-hilk
            So now C++ has found another use for ->! And I assume the [=] is an array holding this as the context or something, is that a special meaning for the =?

            I realize this isn't the place for long discussion, but ISTM with these lambdas C++ is using a lot of cryptic symbols all together!

            J.Hilk 1 Reply Last reply Reply Quote 1
            • S
              sandro4912 last edited by sandro4912

              @jonb said in Connecting to statusBar()->showMessage gives compile time error in new syntax:

              [=]

              [=] means that all the variables / objects are also available in the lamda body for usage. you can also specify there just a single variable from the outside.

              for more see this: https://de.cppreference.com/w/cpp/language/lambda

              the -> you can also use it for normal functions now hence its not that common.

              for example int somefunction(); becomes auto someFunction() -> int

              Anyway guys thanks for the solution

              1 Reply Last reply Reply Quote 2
              • J.Hilk
                J.Hilk Moderators @JonB last edited by

                @jonb
                well, i‘m not sure what exactly the compiler does, but I assume you‘re on the right path:

                [&epsilon] capture by reference
                [&] captures all variables used in the lambda by reference
                [=] captures all variables used in the lambda by value
                [&, epsilon] captures variables like with [&], but epsilon by value
                [=, &epsilon] captures variables like with [=], but epsilon by reference

                which makes this lambda actually dangerous as the statusbar could be deleted at any time, qt offers a solution for this:

                connect(&thread, &TransactionThread::transactionStarted, statusbar, [=](const QString &text)->void{});
                

                the connect get becomes resolved, when statusbar gets deleted

                but from the naming of the variables I would say that the emitter is actually in a different thread compared to statusbar.

                I‘m not sure how Qt handles this with a Lambda, probably not good, therefore 5th connect paramater is probably a good idea

                connect(&thread, &TransactionThread::transactionStarted, statusbar, [=](const QString &text)->void{},Qt::QueuedConnection);
                

                Be aware of the Qt Code of Conduct, when posting : https://forum.qt.io/topic/113070/qt-code-of-conduct

                Qt Needs YOUR vote: https://bugreports.qt.io/browse/QTQAINFRA-4121


                Q: What's that?
                A: It's blue light.
                Q: What does it do?
                A: It turns blue.

                O 1 Reply Last reply Reply Quote 3
                • O
                  ofmrew @J.Hilk last edited by

                  @j-hilk
                  I knew that I had seen this before, try link text

                  1 Reply Last reply Reply Quote 0
                  • S
                    sandro4912 last edited by

                    i tryed to add a fifth parameter like you said:

                        connect(&thread, &TransactionThread::transactionStarted, 
                                [=](const QString &text)->void
                        {
                            statusBar()->showMessage(text);  
                        }, Qt::QueuedConnection);
                    

                    Unfortunatey the syntax is not working with lambda.

                    And yes you are right. In the MainWindow were the statusBar is there is thread launced for taskes to be computed in a second thread.

                    JonB 1 Reply Last reply Reply Quote 0
                    • JonB
                      JonB @sandro4912 last edited by JonB

                      @sandro4912

                      i tryed to add a fifth parameter like you said:

                      Count your parameters, you only have 4!
                      Look at @J-Hilk 's code, see what you've missed....

                      O 1 Reply Last reply Reply Quote 2
                      • O
                        ofmrew @JonB last edited by

                        @jonb

                        Note that the st in [this](const QString& st) is the name of the string that is the argument of the signal, which I use in {this->ui->statusBar->showMessage(st, 0);}

                        O 1 Reply Last reply Reply Quote 0
                        • O
                          ofmrew @ofmrew last edited by

                          @ofmrew
                          Try this example: ```
                          void canvasResized(QString s);
                          QString st = "It opened";
                          emit canvasResized(st);
                          connect(ui->canvas, &MyCanvas::canvasResized, [this](const QString& st){this->ui->statusBar->showMessage(st, 0);});

                          I added the emit to the resizeEvent and it worked.
                          1 Reply Last reply Reply Quote 0
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