@JKSH
2^100 32-bit integers requires 5 x 10^18 TB
Yes, my point was I didn't think that poster's analysis could relate to a real, current situation. Nonetheless, I suppose his mathematical analysis about the behaviour would still hold.
You've also shed some light on something I didn't understand. You're saying 2^100 is somewhere near 10^18 (I know that you're talking about different base units, so I ought to divide by a bit, but still...) Now, I thought my guess of 2^100 sounded a bit low for the supposed number of atoms in the Universe. I have a feeling that figure is something like 10^76 or some such. So 10^n is a lot bigger than 2^n, right? I thought in X^y that the magnitude of y was much more significant than the magnitude of X? I know I could work it out, but how do you figure what m is in 10^m == 2^n?
[Please don't tell me it's m == n/5, that would be too obvious...? Hang on: since 10 == 2^3.something, that means m == n/3.something, so I divide/multiply the exponent by the 3.something to convert between 10^m == 2^n, is that it?! 10^100 == 2^(300+something), 2^100 =~ 10^30-ish?]
It could be a gold digger putting out feelers, as @JonB implied.
Hang on, my reply was intended purely frivolously! I have no reason to imply that the person in question wasn't genuinely interested in the OP. Besides, gold-digging into programmer-geeks is probably not lucrative as we are underpaid & undervalues (speaking for myself) :)
Whatever the case, it sounds like you handled the situation well!
I'd have asked for her phone number ;-)
In the modern world perhaps we are not allowed to jest about these things, so we'd better stick to the question about exponents above....