[solved] QQmlListProperty from QList
-
All the examples I've found online say to do what I've done in the following example, however I get an error.
@QQmlListProperty<QString> ReadXML::listElements()
{
QList<QString> eleList;
eleList.append("one");
eleList.append("two");
eleList.append("three");return QQmlListProperty<QString>(this, eleList);}@
@readxml.cpp:14: error: C2665: 'QQmlListProperty<QString>::QQmlListProperty' : none of the 5 overloads could convert all the argument types
d:\qt\qt5.3.2\5.3\msvc2013_opengl\include\qtqml\qqmllist.h(67): could be 'QQmlListProperty<QString>::QQmlListProperty(QObject *,QList<T *> &)'
with
[
T=QString
]
while trying to match the argument list '(ReadXML *const , QList<QString>)'@Due to the lack of information given by the compiler I don't know how to troubleshoot it. It sounds as if it is telling me to do this:
@return QQmlListProperty<QString>(this, eleList<QString>);@
But that just results in it complaining:
@readxml.cpp:14: error: C2275: 'QString' : illegal use of this type as an expression@I would appreciate any help.
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From the declaration QQmlListProperty(QObject ,QList<T > &) requires a list of the pointers to some type.
You are providing a list of types.
Try this
@
QQmlListProperty<QString> ReadXML::listElements()
{
QList<QString> eleList;
QStringList sourceList;
source << "one" << "two" << "three";
for(QString source : sourceList) {
QString string = new QString(source);
eleList.append(string);
}
return QQmlListProperty<QString>(this, eleList);
}
@ -
But are you trying to pass a list of QString ?!?! If yes, then QStringList is already QML friendly. So, you don't need to create a QQmlListProperty for containing a list of QString, just return a QStringList from the slot:
@
QStringList ReadXML::listElements() {
QStringList eleList;
eleList.append("one");
eleList.append("two");
eleList.append("three");
return eleList;
}
@
