@jsulm said in QtAxContainer.QAxWidget can't from RDP control my windows computer:
@Tian-Sen You should add error handling.
There are https://doc.qt.io/qt-6/qaxbasewidget.html#exception and https://doc.qt.io/qt-6/qaxbasewidget.html#signal signals. Connect slots to them and see what happens. I guess Connect() hangs and since you're calling it in constructor the UI is not initialised properly.
from PySide6.QtWidgets import QApplication, QMainWindow
from PySide6.QtAxContainer import QAxWidget
import sys
class RemoteDesktopWindow(QMainWindow):
def init(self, server_ip, username, password):
super().init()
self.axWidget = QAxWidget("MsRdpClient")
self.axWidget.setControl("{54a2cb42-4f7d-4a07-8c5c-bc0e9e4f3a3a}")
self.axWidget.dynamicCall("SetServer", server_ip)
self.axWidget.dynamicCall("SetUserName", username)
self.axWidget.dynamicCall("SetClearTextPassword", password)
self.axWidget.dynamicCall("Connect()")
print("连接远程桌面")
# 将信号连接到槽以进行错误处理
self.axWidget.exception.connect(self.handle_exception)
self.axWidget.signal.connect(self.handle_signal)
def handle_exception(self, excep_info):
# 在这里处理异常
print("发生异常：", excep_info)
def handle_signal(self, signal, argc, argv):
# 在这里处理信号
print("收到信号：", signal, argc, argv)
if name == "main":
app = QApplication(sys.argv)
window = RemoteDesktopWindow("1", "DESKTOP-0QR3E2C\testserver", "1234.abcde")
window.show()
sys.exit(app.exec())
i have to set it ,but it don't work ,it just print 连接远程桌面 ,the method handle_exception and handle_signal is not work.
